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Apr 18, 2022 at 7:44 vote accept Uzu Lim
Apr 18, 2022 at 7:44 answer added Uzu Lim timeline score: 3
Apr 12, 2021 at 14:27 history edited Uzu Lim CC BY-SA 4.0
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Apr 12, 2021 at 14:25 comment added Uzu Lim Ah, I forgot to specify that. Assume that it's the spectral norm (the 2-norm). However, the Frobenius norm is also fine since $\|A\|_2 \le \|A\|_F\le \sqrt{d} \|A\|_2$ when $d$ is the ambient dimension.
Apr 12, 2021 at 14:05 comment added Bill Bradley Your question uses a matrix norm; just to check, you're talking about the Frobenius norm there, right? (There seems to be literature on a variety of norms.)
Apr 12, 2021 at 0:56 history asked Uzu Lim CC BY-SA 4.0