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Apr 12, 2021 at 7:12 comment added mike I may not understand what A is. I thought A = $\{(t,x) \in [0,T] \times (0,+\infty) \} $ and the condition $ 0 \leq y \leq L$ didn't really belong in the braces, so that the probability you are looking for is the probability that the diffusion becomes positive before time T.
Apr 11, 2021 at 10:05 comment added RedLapm Thank you, even if in the article that I'm reading they state that the probability is less than c/y^2 where c is a positive constant, how can I justify it?
Apr 11, 2021 at 8:16 comment added mike Except when y=0, the answer is 1, because you have started it in that interval. I think the solution starting from 0 is always 0, and so it never enters the stricly positives.
Apr 10, 2021 at 8:34 review First posts
Apr 10, 2021 at 9:46
Apr 10, 2021 at 8:26 history asked RedLapm CC BY-SA 4.0