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Apr 13, 2021 at 15:13 vote accept Piotr Pstrągowski
Apr 8, 2021 at 22:23 history became hot network question
Apr 8, 2021 at 15:37 answer added Gregory Arone timeline score: 5
Apr 8, 2021 at 15:09 comment added Maxime Ramzi So you want something like a cohomological bound on $Tw(I)$, namely you want the derived limit functors to always vanish above some degree. It will also be related to $|I|$, which you want to have finite cohomological dimension, and the derived limit functors on $I$, which you also wanto vanish above some degree.For the latter two, some bound on the dimension of $I$ is enough, but I'm not sure about the first one
Apr 8, 2021 at 15:09 comment added Gregory Arone Suppose the simplicial nerve of $I$ has simplicial dimension $m$. Maybe I am confused, but it seems to me that in this case Fun$(I, A)$ has global dimension $m+n$.
Apr 8, 2021 at 14:22 history asked Piotr Pstrągowski CC BY-SA 4.0