Timeline for How to make commutative algebraic groups strongly dualizable?
Current License: CC BY-SA 2.5
3 events
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| Nov 3, 2009 at 9:39 | history | edited | S. Carnahan♦ | CC BY-SA 2.5 |
response to edited question
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| Nov 3, 2009 at 8:16 | comment | added | Ilya Nikokoshev |
I've started rewriting the question, it was indeed unclear. As for Greg Stevenson's answer, to say that he basically answered my question is to say that for groups A, B the Hom(A, B) = A^*\otimes B makes lots of sense. This might be a well-known thing I'm not aware of, could you clarify it a bit?
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| Nov 3, 2009 at 3:40 | history | answered | S. Carnahan♦ | CC BY-SA 2.5 |