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Jul 5, 2021 at 20:43 comment added Grigor it seems you could just use Sigma^1_3 absoluteness and get an inner model of ZFC+MM^++ in L[mu], no? repeat 0^# argument but with a measurable, like Gabe is doing below, iterability is Pi^1_2, so you don't need Woodins, just Sigma^1_3 abs.
Apr 1, 2021 at 16:29 comment added Monroe Eskew @Zoorado This is a current conjecture as far as I understand. Namely that some strong hypothesis should imply that the HOD of a canonical inner model of AD (larger than $L(\mathbb R)$) should contain large enough cardinals to force PFA.
Apr 1, 2021 at 11:01 comment added Zoorado Yes, you are right. I was mainly curious if there were proper extensions of ZF+AD which can give rise to inner models of ZFC+PFA.
Apr 1, 2021 at 10:36 comment added Asaf Karagila @Zoorado: PFA implies $\sf AD$ in $L(\Bbb R)$, and I seem to recall that it implies even more than just that. If that is indeed the case, then Con(ZFC+PFA) is strictly greater than Con(ZF+AD).
Apr 1, 2021 at 9:46 comment added Monroe Eskew @Zoorado Yes, that sounds right.
Apr 1, 2021 at 9:42 comment added Zoorado Am I right to say that, if I replace $\mathrm{MA}$ with $\mathrm{PFA}$ in the first question, the answer is also unknown?
Apr 1, 2021 at 9:41 vote accept Zoorado
Apr 1, 2021 at 9:37 history answered Monroe Eskew CC BY-SA 4.0