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Apr 1, 2021 at 9:31 comment added Ma Joad Thank you. Let me have a look.
Apr 1, 2021 at 9:30 vote accept Ma Joad
Apr 1, 2021 at 1:26 comment added sharpend (If this answer is helpful, you can consider accepting it.)
Apr 1, 2021 at 1:24 comment added sharpend Sure, the proof uses a subclass of entropies, but (if I remember correctly) there is a way to recover all convex entropies from the subclass. Maybe you can have a look at, say, Bressan's book on conservation laws for more details. I'm sure his presentation is much better than the ad hoc one I give here. One way to see the importance of convexity is from the viscous equation I mentioned in (4). Multiply that equation by $\eta'(u^\nu)$. Notice that $\Delta \eta = \nabla \cdot (\eta' \nabla u^\nu) = \eta' \Delta u^\nu + \eta'' |\nabla u^\nu|^2$. What does $\eta'' \geq 0$ do in that equation?
Mar 31, 2021 at 23:31 comment added Ma Joad And why are we requiring this for all convex $\eta$? Apparently the proof only uses a much smaller class of "entropy" $\eta$ for energy estimates. Also, are there any intuitive way to understand why it needs to be convex?
Mar 31, 2021 at 23:25 comment added Ma Joad So $\psi(u)$ is the "flow" of entropy which is designed to be just right for the equation to hold?
Mar 31, 2021 at 22:52 comment added sharpend When $u$ is smooth, the equation for $\eta(u)$ is $\partial_t \eta(u) + \partial_x \psi(u) = 0$, so when you integrate in $x$, you have $\frac{d}{dt} \int \eta(u) \, dx = 0$, that is, $\int \eta \, dx$ is conserved. When $u$ is not smooth, we require that $\partial_t \eta(u) + \partial_x \psi(u) \leq 0$ is satisfied, and the equation you wrote in (3) is the weak formulation of that.
Mar 31, 2021 at 22:44 comment added Ma Joad By "equivalent" I just mean "one implies another", which is not the case here since we are working with different class of equations. And a priori, before proving the uniqueness, it is not easy to see the conditions actually implies the same thing.
Mar 31, 2021 at 22:40 comment added Ma Joad Why does condition 3 mean "conservation of entropy"? It does not look like familiar conservation laws in physics. Could you explain it a bit more? Thank you.
Mar 31, 2021 at 22:00 history answered sharpend CC BY-SA 4.0