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Apr 1, 2021 at 18:16 comment added David Lampert Note: if $R \rightarrow S$ has finite kernel and finite cokernel then the same is true for $R^* \rightarrow S^*$.
Apr 1, 2021 at 17:15 history edited Mare CC BY-SA 4.0
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Mar 31, 2021 at 13:50 comment added R.P. This could be interesting to you: arxiv.org/abs/1701.02341
Mar 31, 2021 at 13:43 comment added Neil Strickland My guess is that if you choose a random ideal $I\leq R=\mathbb{Z}[x_1,\dotsc,x_n]$ with not too many generators, then $R/I$ will usually be an integral domain with $(R/I)^\times=\{1,-1\}$. If so, then there is no hope of a classification.
Mar 31, 2021 at 13:24 history asked Mare CC BY-SA 4.0