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Mar 29, 2021 at 21:19 comment added Ivan Pong I used the initial guess $a+1 \sim (\sqrt{a}+1)^2$ and the applied difference of squares to cancel out the $2\sqrt{a}$ term.
Mar 29, 2021 at 21:16 comment added Will Brian This answer reminds me of Frank Nelson Cole (mathoverflow.net/questions/207321/…). How did you find this factorization?
Mar 29, 2021 at 21:08 vote accept Ivan Pong
Mar 29, 2021 at 21:08 history answered Ivan Pong CC BY-SA 4.0