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Mar 29, 2021 at 6:57 vote accept Ma Joad
Mar 28, 2021 at 21:05 answer added Christian Remling timeline score: 1
Mar 28, 2021 at 20:28 comment added Nate Eldredge Trivial comment: the operators $u \mapsto u \ast \phi_\epsilon$ are uniformly bounded by Young's inequality or the uniform boundedness principle. Hence they are equicontinuous and so converge uniformly on compact sets. Thus you get it whenever $H^s$ is compactly embedded in $L^2$. I don't recall offhand which values of $s$ make this true, though.
Mar 28, 2021 at 19:44 history asked Ma Joad CC BY-SA 4.0