Timeline for Is $L^p(\mathbb{R})$ minus the zero function contractible?
Current License: CC BY-SA 2.5
11 events
when toggle format | what | by | license | comment | |
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Feb 24, 2014 at 14:22 | comment | added | Gerald Edgar | All separable, infinite-dimensional Banach spaces are homeomorphic to each other (and to $\mathbb R^\infty$), so if you like you can use one of those other spaces. | |
Jan 13, 2014 at 21:21 | answer | added | Sam Nead | timeline score: 2 | |
Sep 15, 2010 at 8:09 | comment | added | Andrew Stacey | Meta discussion on whether to close as duplicate or not: tea.mathoverflow.net/discussion/672/are-these-duplicates | |
Sep 15, 2010 at 7:50 | comment | added | Andrew Stacey | (Looking again at my answer to the contractiblity of the sphere, I realised one could weaken the conditions so the "stable" in the above is stronger than needed.) | |
Sep 15, 2010 at 7:18 | comment | added | Andrew Stacey | Technically, this is a duplicate of: mathoverflow.net/questions/198/… , my answer there works for any space that is "stable" in the sense that $X \oplus \mathbb{R} \cong X$. | |
Sep 15, 2010 at 5:54 | answer | added | Dick Palais | timeline score: 8 | |
Sep 15, 2010 at 4:03 | vote | accept | Nikita | ||
Sep 15, 2010 at 3:36 | answer | added | fedja | timeline score: 23 | |
Sep 15, 2010 at 3:16 | answer | added | Richard Borcherds | timeline score: 7 | |
Sep 15, 2010 at 2:30 | answer | added | Bill Johnson | timeline score: 14 | |
Sep 15, 2010 at 2:15 | history | asked | Nikita | CC BY-SA 2.5 |