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Dec 20, 2021 at 20:02 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
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Mar 25, 2021 at 17:13 answer added Igor Khavkine timeline score: 1
Mar 25, 2021 at 16:37 comment added EdRich @IgorKhavkine I'm not exactly sure what you mean by compatible, but in general if $w \in W_i$ then $\mathcal{Q}(w) \in W_{i+1}$. I will put this in the question. My main difficulty lies in actually constructing $\phi_i$, if that is the correct approach. I'm not sure how to do this in principle.
Mar 25, 2021 at 16:36 history edited EdRich CC BY-SA 4.0
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Mar 25, 2021 at 16:00 comment added Igor Khavkine Are the inclusions $W_i \subset V_i$ somehow compatible with $\mathcal{Q}$? If not, there's probably no unique way to define $\mathcal{Q}_\perp$ and you could do what you like. You should probably add the relevant information about the relation between $W_i$ and $\mathcal{Q}$ to your question.
Mar 25, 2021 at 15:18 history edited EdRich
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Mar 25, 2021 at 6:21
Mar 24, 2021 at 23:47 history asked EdRich CC BY-SA 4.0