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Mar 22, 2021 at 17:08 vote accept Stefano D'Alesio
Mar 21, 2021 at 15:37 answer added Simon Henry timeline score: 3
Mar 21, 2021 at 14:43 comment added Chris Schommer-Pries An example where the abelianization functor does not exist: take $\mathcal{C}$ to be the category of sets whose cardinality is either 1 or infinite with the product monoidal structure. Infinite groups are examples of monoids in this category. There are infinite groups whose (standard) abelianization is a non-trivial finite group, and these won't exist as commutative monoid objects in $\mathcal{C}$.
Mar 21, 2021 at 12:02 comment added fosco In full generality, the existence of left adjoints is linked to the existence of colimits; all in all, abelianisation will exist in every category of internal monoids in $C$ such that $U : Ab(C) \to Mon(C)$ satisfies the assumptions of the adjoint functor theorem.
Mar 21, 2021 at 10:17 review First posts
Mar 21, 2021 at 12:37
Mar 21, 2021 at 10:14 history asked Stefano D'Alesio CC BY-SA 4.0