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Mar 20, 2021 at 10:37 comment added Leo Moos @PierrePC Oops, my bad. In any case I'm glad it worked out in this way.
Mar 20, 2021 at 4:54 answer added Pierre PC timeline score: 5
Mar 20, 2021 at 3:21 comment added Pierre PC It is polynomial in $\rho$ but exponential in $d$. I think your reasoning shows it is at most $(1/\varepsilon)^d$, up to a constant and for $\rho=\cos(\varepsilon)$, or something similar.
Mar 20, 2021 at 3:07 comment added Leo Moos How you come you expect an exponential bound? I'm a bit confused - what is the obstruction to a polynomial bound, perhaps obtained by summing the areas of disjoint discs centered at the points?
Mar 20, 2021 at 2:56 comment added Probabilist @MattF.You are right, I want bounded above. Changed it.
Mar 20, 2021 at 2:55 history edited Probabilist CC BY-SA 4.0
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Mar 20, 2021 at 2:12 comment added user44143 Do you want the inner products bounded above? If you want them bounded below you can take arbitrarily many that are all close to the same vector
Mar 20, 2021 at 2:08 history edited RobPratt CC BY-SA 4.0
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Mar 20, 2021 at 1:22 history asked Probabilist CC BY-SA 4.0