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Mar 17, 2021 at 16:59 comment added Luigi M thanks a lot! everything makes much more sense now!
Mar 17, 2021 at 16:58 vote accept Luigi M
Mar 17, 2021 at 16:18 comment added Chris Gerig Because I’m assuming the manifold is not a blowup. Use adjunction inequality to see that $\chi(C) + 2[C]^2 \ge0$.
Mar 17, 2021 at 16:17 comment added Luigi M I see, thanks a lot for the clarification Chris. but then in your answer, how do you exclude the case $[C]^2 <0$ (which I think is the reason why you can conclude that either $k=1$ or is a square zero torus)
Mar 17, 2021 at 15:59 comment added Chris Gerig They can certainly be J-holomorphic (your comment about forbidding negative self-intersection is false), consider the blowup of CP2 with standard complex structure and the exceptional divisor. Anyway, multiple covers will have negative virtual dimension.
Mar 17, 2021 at 15:57 comment added Luigi M Dear Chris, thanks a lot! can I ask you why exceptional spheres might cause a problem? they are not $J$-hol since by definition they have negative self-intersection, how do they arise in this context?
Mar 17, 2021 at 15:08 history answered Chris Gerig CC BY-SA 4.0