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Mar 16, 2021 at 18:14 comment added Will Sawin You can probably embed any $3$-manifold in this way after removing a bunch of open balls, but that's less exciting.
Mar 16, 2021 at 18:13 comment added Will Sawin Nice! I wondered whether you can generalize this construction to get an arbitrary 3-manifold by using a Heegard splitting instead of a fibration, and somehow using degenerate fibers to embed the two handlebodies (and using a path between two degenerate fibers rather than a loop in the fundamental group). Unfortunately, you can't, because the surface in a Heegard splitting always represents a trivial homology class, while the fiber curve in an algebraic surface represents a nontrivial homology class.
Mar 16, 2021 at 18:00 history edited Moishe Kohan CC BY-SA 4.0
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Mar 16, 2021 at 17:49 history answered Moishe Kohan CC BY-SA 4.0