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Mar 20, 2021 at 20:13 comment added Mikhail Borovoi Thus we come to ${\rm Ext}({\rm Res \,GL}_1,\mu_2)$ and ${\rm Ext}({\rm Res\,U}_1,\mu_2)$. I think that Res does not change Ext, and so we come to ${\rm Ext}({\rm GL}_1,\mu_2)$ and ${\rm Ext}({\rm U}_1,\mu_2)$. Each of them has cardinality 2, the nontrivial extensions being the standard double covers $$\rm GL_1\overset 2 \longrightarrow GL_1\quad\text{and}\quad \rm U_1\overset 2 \longrightarrow U_1\,.$$ Among those $H^1(F,\rm U_1)\ne 1$.
Mar 20, 2021 at 19:44 comment added Mikhail Borovoi Let us call ${\rm Ext}(G,\mu_2)$ the set of isomorphism classes of these extensions. I think that the homomorphism $G\to G^{\rm tor}$ induces an isomorphism $${\rm Ext}(G^{\rm tor},\mu_2)\overset{\sim}{\longrightarrow} {\rm Ext}(G,\mu_2),$$ where $G^{\rm tor}=G/(G,G)$ (the quotient by the commutator subgroup), because $(G,G)$ is simply connected.
Mar 20, 2021 at 19:33 history edited Mikhail Borovoi
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Mar 15, 2021 at 14:59 history edited Mikhail Borovoi
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Mar 15, 2021 at 14:49 history edited Mikhail Borovoi
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Mar 15, 2021 at 7:09 comment added მამუკა ჯიბლაძე What kind of extension is $E$?
Mar 15, 2021 at 2:43 history asked Windi CC BY-SA 4.0