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Mar 26, 2021 at 20:14 comment added username Hatcher's Algebraic Geometry is very useful (Pierre Albin's lectures on this book are very helpful) to understand your answer. Yet I think your answer doesn't answer my question, it describes what the space looks like, and why I cannot map to $\mathbb{R}$. I think the answer to my question is simply "yes" : there is a lift taking values in $\mathbb R/2\pi\mathbb Z$.
Mar 26, 2021 at 20:04 vote accept username
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Mar 26, 2021 at 20:04
Mar 12, 2021 at 15:05 vote accept username
Mar 26, 2021 at 20:04
Mar 12, 2021 at 12:31 comment added Thomas Rot You can have a look at Hatcher's algebraic topology book. This is discussed in the section on the fundamental group and covering spaces.
Mar 12, 2021 at 12:30 history edited Thomas Rot CC BY-SA 4.0
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Mar 12, 2021 at 12:30 comment added Thomas Rot in the case described the subgroup is $\mathbb Z$ itself.
Mar 12, 2021 at 11:17 comment added username Thank you that is probably very helpful --that's not a language I am familiar with but I'll try to understand what it means. To take the example of $x/|x|$ in the domain described, which subgroups would it belong to? Is there such as thing as a lift from $\mathbb{R}/2\pi\mathbb{Z}$ to $S^1$?
Mar 12, 2021 at 9:37 history answered Thomas Rot CC BY-SA 4.0