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Mar 11, 2021 at 16:17 comment added mme @user51223 The product topology, as always. That this map exists and is continuous follows from the universal property of the product topology. Exercise in universal property: if $f_i: X_i \to X_i$ is a family of continuous maps, then $\prod f_i: \prod_{i \in I} X_i \to \prod_{i \in I} X_i$ is a continuous map. All of Dmitri's statements about the induced maps etc similarly follow from the universal property.
Mar 11, 2021 at 15:48 comment added user51223 What is the topology on this product? I feel it is important, but don’t have any argument against your example.
Mar 11, 2021 at 14:32 history answered Dmitri Pavlov CC BY-SA 4.0