Timeline for residue calculation for rational function
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| Mar 11, 2021 at 5:17 | history | edited | Michael Hardy | CC BY-SA 4.0 |
added 9 characters in body
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| Mar 10, 2021 at 21:50 | comment | added | Neil Strickland | If m does not divide $kn$ then the residue at $\omega r$ will be $\omega^p$ times the residue at $r$ for some $p\neq 0\pmod{m}$ so the sum of the residues at finite poles will be zero, as will the residue at $\infty$. There may be some more subtle way to adapt the argument. I tried a couple of things that did not work, but I did not spend a long time on it. | |
| Mar 10, 2021 at 20:43 | vote | accept | Alice | ||
| Mar 10, 2021 at 20:43 | comment | added | Alice | That is really neat! Thanks so much for that! In principle, the same idea (looking at the residue at $\infty$) should work regardless of whether m divides kn or not, shouldn't it? | |
| Mar 10, 2021 at 16:33 | history | answered | Neil Strickland | CC BY-SA 4.0 |