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David White
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Let H$H$ be any group and let G$G$ the direct product of Z$\mathbb{Z}$ and H$H$. ByBy sending all elements of H$H$ to the the identity, you can see that G$G$ is also a separator. It is easy to construct lots more examples along these lines (any group with Z$\mathbb{Z}$ as a quotient will do, for starters).

Let H be any group and let G the direct product of Z and H. By sending all elements of H to the identity, you can see that G is also a separator. It is easy to construct lots more examples along these lines (any group with Z as a quotient will do, for starters).

Let $H$ be any group and let $G$ the direct product of $\mathbb{Z}$ and $H$. By sending all elements of $H$ to the identity, you can see that $G$ is also a separator. It is easy to construct lots more examples along these lines (any group with $\mathbb{Z}$ as a quotient will do, for starters).

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Daniel Groves
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Let H be any group and let G the direct product of Z and H. By sending all elements of H to the identity, you can see that G is also a separator. It is easy to construct lots more examples along these lines (any group with Z as a quotient will do, for starters).