Timeline for Is delta function symmetric against real axis?
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
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| Mar 9, 2021 at 8:53 | comment | added | Anixx | I am judging from the Fourier transform-based definition. Yes, it seems not symmetric under rotations. | |
| Mar 9, 2021 at 8:48 | comment | added | bathalf15320 | If you are seriouly claiming that the delta distribution is NOT symmetric under rotations, then I'm outta here! | |
| Mar 9, 2021 at 8:43 | history | edited | bathalf15320 | CC BY-SA 4.0 |
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| Mar 9, 2021 at 8:32 | comment | added | Anixx | Also, according to the linked result, $\int_{-\infty}^\infty \delta(t+bi)f(t)dt=f(-bi)\ne f(bi)=\int_{-\infty}^\infty \delta(t-bi)f(t)dt$ | |
| Mar 9, 2021 at 8:26 | comment | added | Anixx | How it is symmetric with respect to rotation if $\delta(i) = \frac{1}{2\pi}\int_{-\infty}^\infty e^{-t}\, dt$, which is divergent to infinity, while $\delta(1)=0$? | |
| Mar 9, 2021 at 8:20 | history | answered | bathalf15320 | CC BY-SA 4.0 |