Timeline for Confining a polytope to one side of an affine hyperplane
Current License: CC BY-SA 4.0
16 events
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| Jul 1, 2021 at 14:14 | comment | added | YCor | Meta question about the accepted answer to this question: meta.mathoverflow.net/questions/5084/… | |
| S Jun 26, 2021 at 17:17 | vote | accept | Hans | ||
| Jun 26, 2021 at 16:54 | answer | added | Hans | timeline score: 0 | |
| Mar 17, 2021 at 12:22 | vote | accept | Hans | ||
| S Jun 26, 2021 at 17:17 | |||||
| Mar 12, 2021 at 11:16 | answer | added | Dima Pasechnik | timeline score: 6 | |
| Mar 10, 2021 at 7:27 | history | edited | gmvh |
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| Mar 10, 2021 at 1:28 | vote | accept | Hans | ||
| Mar 10, 2021 at 3:31 | |||||
| Mar 9, 2021 at 19:50 | answer | added | Hans | timeline score: 0 | |
| Mar 9, 2021 at 2:36 | history | edited | Hans | CC BY-SA 4.0 |
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| Mar 5, 2021 at 10:58 | answer | added | Dima Pasechnik | timeline score: 2 | |
| Mar 4, 2021 at 23:45 | comment | added | Dima Pasechnik | P* contains the inequalities valid for P. Vertices of P* are facets of P, convex linear combinations of vertices of P* are, in general, less tight inequalities valid for P, what is unclear? Try this on a 4 gon in plane... | |
| Mar 4, 2021 at 23:19 | comment | added | Hans | @DimaPasechnik: I do not understand your comment. I just looked up the definition of a dual polytope. It seems to me that however this other polytope is configured, so long as it is not the complement of $P$, the iff does not seem to hold. What am I missing? Could you please elaborate? | |
| Mar 4, 2021 at 22:00 | comment | added | Dima Pasechnik | look at the dual polytope P* of P. Then your halfspace does not cut P iff it is contained in P*, more or less by definition of the dual polytope. | |
| Mar 4, 2021 at 20:01 | history | edited | Hans | CC BY-SA 4.0 |
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| Mar 4, 2021 at 19:16 | review | Close votes | |||
| Mar 12, 2021 at 10:44 | |||||
| Mar 4, 2021 at 18:50 | history | asked | Hans | CC BY-SA 4.0 |