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Mar 1, 2011 at 4:54 answer added Aaron Meyerowitz timeline score: 1
Oct 11, 2010 at 14:16 comment added Roland Bacher Nice reformulation!
Oct 11, 2010 at 13:58 comment added Dave Pritchard Maybe it is easier to reformulate in the following way: two vertices $u, v$ are in the same partition iff $\sum_T d_T(u, v)$ is even, where the inner expression is the distance in the tree. Is there a nice way to compute this distance sum mod 2?
Sep 13, 2010 at 21:57 comment added JBL Apurva, there's a product over all spanning trees.
Sep 13, 2010 at 21:36 comment added Apurva Is the spanning tree $T$ a given at the beginning of this problem, or is it a part of the problem to also find the spanning tree?
Sep 13, 2010 at 16:05 comment added Roland Bacher Thank you. That's a typical error of french-speaking people, I guess.
Sep 13, 2010 at 14:19 comment added JBL @Roland, in English "to ignore" means "to refuse to notice; to disregard" -- to convey "to not know" one can write "to be ignorant of."
Sep 13, 2010 at 13:48 comment added Roland Bacher Concerning the name of this bipartition, I ignore the answer. Concernings Austin Mohr's remark: Of course, the function is only used for defining an equivalence relation with at most two classes on the set of vertices.
Sep 13, 2010 at 13:06 comment added Austin Mohr Just a minor point: Your function appears to be defined on $V(\Gamma) \times V(\Gamma)$, as $\phi_T$ only has a meaningful output when given two vertices.
Sep 13, 2010 at 11:50 comment added Nathann Cohen Does this partition have a name ? :-)
Sep 13, 2010 at 11:19 answer added sleepless in beantown timeline score: 0
Sep 13, 2010 at 8:07 history asked Roland Bacher CC BY-SA 2.5