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Mar 3, 2021 at 21:56 vote accept frafour
Mar 3, 2021 at 20:27 comment added user42024 @frafour Yep that's right $\sigma$ is the action of a chosen generator and $1=\mathrm{id}$ is the identity map. I am not sure about the precise reference (probably anything on Tate cohomology) but this just follows from the fact that the analogous complex $\ldots \xrightarrow{1+\sigma +\ldots } \mathbb Z[G] \xrightarrow{\sigma - \mathrm{id}} \mathbb Z[G]$ is a free resolution of trivial module $\mathbb Z$ as a $\mathbb Z[G]$-module (plus the formula $H^i(G,M)=\mathrm{Ext}^i_{\mathbb Z[G]}(\mathbb Z,M)$).
Mar 3, 2021 at 17:05 comment added frafour Thank you very much for the answer! To be sure: $\sigma$ is the automorphism given by the action of the generator of $G$? And $1$ is the identity map? Also could you give a reference for the first statement, the fact that cohomology is computed by this resolution?
Mar 2, 2021 at 20:48 history answered user42024 CC BY-SA 4.0