Timeline for Is it true that the structure of a commutative ordered semiring is unique on a commutative ordered monoid?
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Oct 28, 2021 at 20:37 | answer | added | Pace Nielsen | timeline score: 5 | |
| Oct 28, 2021 at 18:36 | history | edited | Arshak Aivazian | CC BY-SA 4.0 |
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| Mar 15, 2021 at 1:55 | history | edited | Arshak Aivazian | CC BY-SA 4.0 |
added 277 characters in body
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| Mar 15, 2021 at 1:49 | comment | added | Arshak Aivazian | @dodd Yes, sorry, I will clarify the question. | |
| Mar 15, 2021 at 1:47 | comment | added | Arshak Aivazian | @BenjaminSteinberg I really meant that the original monoid corresponds to the additive ring monoid. | |
| Feb 26, 2021 at 11:09 | comment | added | Benjamin Steinberg | It might help to explain whether you want to turn the additive structure into a semiring or the multiplicative one | |
| Feb 26, 2021 at 6:20 | comment | added | markvs | You can always turn an additive commutative monoid into a semiring by setting $xy=0$ for all $x,y$. | |
| Feb 26, 2021 at 3:06 | history | asked | Arshak Aivazian | CC BY-SA 4.0 |