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Feb 22, 2021 at 14:33 comment added MikeG @WillieWong Thanks, I have found that also. Actually I prefer that in Rmk 0.2 in this doc which uses less advanced results. I am very very interested in MaoWao's comment about the relationship between recurrence of BM and bdd subharmonic function being constant. Do you have any idea about this?
Feb 22, 2021 at 13:37 comment added Willie Wong A proof of the Liouville theorem for subharmonic functions on the plane is given in this MSE post by way of the Hadamard Three Circle Theorem.
Feb 22, 2021 at 13:34 history became hot network question
Feb 22, 2021 at 6:51 vote accept MikeG
Feb 22, 2021 at 6:51 comment added MikeG @MaoWao: where can I find materials discussing this issue?
Feb 22, 2021 at 6:39 comment added MaoWao The Brownian motion on $\mathbb{R}^2$ is recurrent, which implies that every bounded subharmonic function is constant.
Feb 22, 2021 at 6:31 answer added Willie Wong timeline score: 5
Feb 22, 2021 at 6:18 comment added Willie Wong In dimension $n \geq 3$, a non-explicit way: choose your favourite strictly positive Schwartz class function $\chi$ (say, the Gaussian). Its Fourier transform is also Schwartz. So $\hat{\chi}(\xi) / |\xi|^2$ is in $L^1$ and of rapid decay, and you can apply the Fourier inversion formula to get $\triangle^{-1} \chi$ which will give you a smooth example. Alternatively just take an arbitrary positive Schwartz function and convolve with $|x|^{2-n}$. In $\mathbb{R}^2$ I am pretty sure this is ruled out by a version of Liouville's theorem.
Feb 22, 2021 at 5:44 comment added MikeG Thank you!@Daniele
Feb 22, 2021 at 5:41 history edited Daniele Tampieri CC BY-SA 4.0
Minor Math Jaxing (proper bracket scaling and $exp\to\exp$
Feb 22, 2021 at 5:33 review First posts
Feb 22, 2021 at 6:47
Feb 22, 2021 at 5:32 history asked MikeG CC BY-SA 4.0