Timeline for What are conditions such that the polynomial $x^2+1$ divides $p(y)+q(z)+ax+b=F(x,\, y, \,z)$? [closed]
Current License: CC BY-SA 4.0
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| when toggle format | what | by | license | comment | |
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| Feb 23, 2021 at 23:12 | history | closed |
Emil Jeřábek user44191 skupers Friedrich Knop leo monsaingeon |
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| Feb 20, 2021 at 15:56 | vote | accept | Safwane | ||
| Feb 20, 2021 at 12:20 | history | edited | Francesco Polizzi | CC BY-SA 4.0 |
deleted 11 characters in body
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| Feb 20, 2021 at 12:01 | review | Close votes | |||
| Feb 23, 2021 at 23:12 | |||||
| Feb 20, 2021 at 11:24 | answer | added | Per Alexandersson | timeline score: 2 | |
| Feb 20, 2021 at 11:18 | comment | added | Per Alexandersson | It should be the case that F(i,y,z) = F(-i,y,z) = 0, where i is the square root of -1. But, this seems to imply that $a=0$, and thus, your polynomial must be identically 0. Let me make that into an answer. | |
| Feb 20, 2021 at 10:56 | history | asked | Safwane | CC BY-SA 4.0 |