Timeline for Action of the Casimir on highest weight modules for Kac-Moody algebra
Current License: CC BY-SA 4.0
11 events
when toggle format | what | by | license | comment | |
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Feb 24, 2021 at 4:50 | vote | accept | tudong | ||
Feb 22, 2021 at 18:08 | answer | added | SamJeralds | timeline score: 1 | |
Feb 20, 2021 at 0:38 | comment | added | tudong | Yes, the form invariant means $(ad x \cdot y|z)+(y,adx\cdot z)=0$. | |
Feb 19, 2021 at 14:52 | history | edited | Francesco Polizzi | CC BY-SA 4.0 |
added 4 characters in body
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Feb 19, 2021 at 14:36 | comment | added | LSpice | The paper @tudong referenced: Kac and Peterson - Infinite flag varieties and conjugacy theorems. | |
Feb 19, 2021 at 14:35 | comment | added | LSpice | Calling the form invariant means $g$-invariant, in the sense that $\operatorname{ad}$ is skew-symmetric with respect to it? | |
Feb 19, 2021 at 14:28 | history | edited | gmvh | CC BY-SA 4.0 |
Improved formatting, added tags
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Feb 19, 2021 at 13:58 | comment | added | tudong | Thank you for your response. The relation is correct. But I want to know the reason, since i am just a beginer in Lie algebra. The relation is just Lemma 3 in D. H. Peterson and V. G. Kac, Infinite flag varieties and conjugacy theorems, Proc, Natl. Acad. Sci, USA, Vol. 80,1983, pp. 1778-1782. | |
Feb 19, 2021 at 13:44 | comment | added | Sam Sanders | Can you perhaps tell us which article/book you got the equation from? And why is the explanation there not satisfactory? | |
Feb 19, 2021 at 13:31 | review | First posts | |||
Feb 19, 2021 at 13:44 | |||||
Feb 19, 2021 at 13:29 | history | asked | tudong | CC BY-SA 4.0 |