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Jul 16, 2022 at 3:30 history edited LSpice CC BY-SA 4.0
Capitalise title, while it's on the front page
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Feb 20, 2021 at 23:05 comment added LSpice I added a link to the MSE question, and, in the process, converted your manually spaced inline math (which I found very hard to read) into the relevant AMSmath environments. I hope that was all right.
Feb 20, 2021 at 23:04 history edited LSpice CC BY-SA 4.0
Link to MSE question; TeXing
Feb 20, 2021 at 22:04 answer added Will Jagy timeline score: 0
Feb 20, 2021 at 1:27 comment added Will Jagy getting systematic about it. Found one with a quick proof, $\langle 5,4,8 \rangle$ because the duplicated form is $\langle 4,0,9 \rangle$ and there are only finitely many solutions to $w^2 - 9 v^2=4$ or $w^2 - 4 v^2 = 9$ Two more from that page $\langle 5,2,13 \rangle$ $\langle 6,2,11 \rangle$
Feb 19, 2021 at 18:16 history edited Will Jagy CC BY-SA 4.0
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Feb 19, 2021 at 17:48 history edited Will Jagy CC BY-SA 4.0
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Feb 19, 2021 at 17:38 history edited Will Jagy CC BY-SA 4.0
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Feb 19, 2021 at 17:36 comment added Will Jagy right. The values indicated by the square root signs in my comment last night come out $1, 7, 17, 19, 23 \pmod {24}$ while the values of $14 x^2 + 8xy + 29 y^2$ that are coprime with $24$ are $5, 11 \pmod{24}$
Feb 19, 2021 at 6:49 history edited Francesco Polizzi CC BY-SA 4.0
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Feb 19, 2021 at 2:12 comment added Will Jagy the integers $\sqrt{39 + 10 v^2}$ and $\sqrt{10 + 39 v^2}$ come out wrong, either $\pmod 3$ or $\pmod 8,$ for values of $14 x^2 + 8 xy + 29 y^2.$ The form is alone in its genus, factoring does not matter...so weird
Feb 19, 2021 at 0:49 history undeleted Will Jagy
Feb 19, 2021 at 0:02 history deleted Will Jagy via Vote
Feb 18, 2021 at 23:36 history edited Will Jagy CC BY-SA 4.0
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Feb 18, 2021 at 23:08 history asked Will Jagy CC BY-SA 4.0