Timeline for Image of a complex disc by this function?
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| Feb 18, 2021 at 18:17 | comment | added | Gerald Edgar | $f(z) = (z+1)/(z-1)$ maps reals to reals, so your image is symmetric about the real axis. Presumably $f(a)$ and $f(-a)$ are the two ends of a diameter. This would let you compute center and radius. | |
| Feb 18, 2021 at 16:58 | vote | accept | lrnv | ||
| Feb 18, 2021 at 16:58 | vote | accept | lrnv | ||
| Feb 18, 2021 at 16:58 | |||||
| Feb 18, 2021 at 16:58 | comment | added | lrnv | I was going to delete the question since the mathematica command ComplexRegionPlot[Abs[(z + 1)/(z - 1)] <= 1.1, {z, 10}] just gave me the same answer. Thanks for the reference to Moebius transforms !!. Do you know how i could get center and radius of this circle ? | |
| Feb 18, 2021 at 16:54 | history | answered | Yemon Choi | CC BY-SA 4.0 |