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Feb 19, 2021 at 18:22 comment added Dmitri Pavlov There is more than one suspension and loop functor in simplicial homotopy theory, but none of them simply shifts simplicial degrees by one. Additionally, for simplicial monoids the suspension functor must be derived, if you are to get a correct answer. If you simply shift simplicial degrees by one, how is the resulting sequence of sets turned into a simplicial set?
Feb 19, 2021 at 10:20 comment added Mathemologist It's just a map into the suspension. I am sorry if my terminology is incorrect. The n-cells of $X^{*}$ are lists of n-cells in $X$, and the suspension shifts the grading by one.
Feb 19, 2021 at 2:20 comment added Dmitri Pavlov Okay, how is a "shifted homomorphism of simplicial monoids" defined?
Feb 19, 2021 at 2:09 comment added Mathemologist Every n-cell in $X$ has a list of faces of length n+1, which is an (n-1)-cell in the free simplicial monoid $X^{*}$. This defines a map $X\to \Sigma X^{*}$, which is the adjunct to a map $X^{*}\to \Sigma X^{*}$. This operation is defined on lists of n-cells, giving you the result of first replacing each list element with its list of faces, and then passing this list-of-lists through the component for the multiplication of the free monoid monad, ie just concatenate the finite list of finite lists (all of whose elements are faces of n-cells).
Feb 18, 2021 at 18:50 comment added Dmitri Pavlov How is the "list of lists of faces of each n-cell" defined?
Feb 18, 2021 at 12:10 history asked Mathemologist CC BY-SA 4.0