Now if we have a complex-valued test function $f\in\mathscr{S}(\mathbb{R},\mathbb{C})$, it holds that $$ \int_{\mathscr{S}'(\mathbb{R}^d,\mathbb{R})} e^{i\varphi(f)}\ d\mu_M(\varphi) =\left\langle \exp\left[i\sum_{x\in\mathbb{Z}}\sigma_x g_x\right] \right\rangle $$$$ \int_{\mathscr{S}'(\mathbb{R},\mathbb{R})} e^{i\varphi(f)}\ d\mu_M(\varphi) =\left\langle \exp\left[i\sum_{x\in\mathbb{Z}}\sigma_x g_x\right] \right\rangle $$ where $g=(g_x)_{x\in\mathbb{Z}}\in \mathcal{s}(\mathbb{Z},\mathbb{C})$ is a discrete test function, with rapid decay on the lattice $\mathbb{Z}$, given by $g_x=L^{-\frac{M}{2}}f(L^{-M}x)$. Since we work with complex-valued test functions, the difference between characteristic functions and moment generating function is moot and amounts to deciding to absorb the $i$ into the test function or not. We will keep it out.
With the above result one can show that for $f\in\mathscr{S}(\mathbb{R},\mathbb{C})$ such that $4eK||f||_{L^{\infty}}||f||_{L^{1}}<1$, $$ \lim\limits_{M\rightarrow \infty} \int_{\mathscr{S}'(\mathbb{R}^d,\mathbb{R})} e^{i\varphi(f)}\ d\mu_M(\varphi) = \exp\left[-\frac{K}{2}\int_{\mathbb{R}}f(x)^2\ dx\right]\ . $$$$ \lim\limits_{M\rightarrow \infty} \int_{\mathscr{S}'(\mathbb{R},\mathbb{R})} e^{i\varphi(f)}\ d\mu_M(\varphi) = \exp\left[-\frac{K}{2}\int_{\mathbb{R}}f(x)^2\ dx\right]\ . $$ Here the constant $K$ is related to the susceptibility and is given by $K=\frac{1+e^{-m}}{1-e^{-m}}$.
Now take $f\in\mathscr{S}(\mathbb{R},\mathbb{R})$, a real-valued test function but this time with no limitation on its size. For $z\in\mathbb{C}$, let $$ G_M(z)=\int_{\mathscr{S}'(\mathbb{R}^d,\mathbb{R})} e^{iz\varphi(f)}\ d\mu_M(\varphi)\ , $$$$ G_M(z)=\int_{\mathscr{S}'(\mathbb{R},\mathbb{R})} e^{iz\varphi(f)}\ d\mu_M(\varphi)\ , $$ which is well defined and analytic in an open horizontal strip around the real axis. The bound for $\mathcal{F}$ shows that $G_M(z)$ is uniformly bounded in $z$ and $M$ on every compact subset of the strip. The Vitali-Porter Theorem then gives pointwise convergence on the real line, and the Lévy Continuity Theorem finishes the job of proving that we weakly converge to $\sqrt{K}$ times white noise.