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Feb 16, 2021 at 17:22 vote accept Igor Belegradek
Feb 16, 2021 at 15:56 comment added Andy Putman @AllenHatcher: Oh, that’s a good point! I had just assumed that Sawashita was correct without thinking very hard about it.
Feb 16, 2021 at 15:36 comment added Allen Hatcher @IgorBelegradek: The theorem of Sawashita appears to be incorrect in the case of $S^1\times S^2$. The kernel is ${\mathbb Z}_2$ rather than ${\mathbb Z}$ (and the extension is a product). The ${\mathbb Z}$ presumably comes from $\pi_1SO(2)$ but it should be $\pi_1SO(3)$, corresponding to a homeomorphism of $S^1\times S^2$ rotating $\{t\}\times S^2$ by the angle $t$. As in my comment to Andy Putman there is no difference between basepoint-preserving homotopy equivalences and those that do not preserve basepoint in this situation.
Feb 16, 2021 at 14:55 comment added Allen Hatcher @AndyPutman: For $S^1\times S^2$ the mapping class group fixing a basepoint is the same as the one with the basepoint not fixed. This is because in the Birman exact sequence the map $\pi_1 {\rm Diff}(S^1\times S^2)\to\pi_1(S^1\times S^2)$ induced by evaluating diffeomorphisms at the basepoint is surjective. (For others: the Birman exact sequence is the exact sequence of homotopy groups for the fibration ${\rm Diff}(S^1\times S^2)\to S^1\times S^2$ given by evaluating at a basepoint, with fiber the basepoint-preserving diffeomorphisms.)
Feb 16, 2021 at 5:12 answer added Allen Hatcher timeline score: 13
Feb 16, 2021 at 4:06 comment added Andy Putman Yes, I think that does it. You could also easily prove from Gluck's theorem that the mapping class group of basepoint-preserving orientation-preserving diffeomorphisms is an extension of $(\mathbb{Z}/2)^2$ by $\mathbb{Z}$ (by the way, I don't know if this split or not). I recently wrote a paper on connect sums of $n$ copies of $S^1 \times S^2$ where we improve a theorem of Laudenbach to show that the mapping class group is a split extension of $Out(F_n)$ by $(\mathbb{Z}/2)^n$, which reduces to Gluck's theorem for $n=1$. See here: arxiv.org/abs/2012.01529
Feb 16, 2021 at 3:35 comment added Igor Belegradek @AndyPutman: thanks! Sawashita in theorem 8.8 of [On the Group of Self-Equivalences of the Product of Spheres", Hiroshima Math J, 1975] projecteuclid.org/download/pdf_1/euclid.hmj/1206136785 computed the group of based homotopy self-equivalences of $S^1\times S^2$; it maps onto $(\mathbb Z_2)^2$ with kernel $\mathbb Z$, and presumably, one can compare the two results and extract what I want. I was just hoping for a clean reference.
Feb 16, 2021 at 3:17 comment added Andy Putman I don't know an earlier proof, but you might be interested in the following paper which shows that the mapping class group of $S^1 \times S^2$ is $(\mathbb{Z}/2)^2$: H. Gluck, The embedding of two-spheres in the four-sphere. Trans. Amer. Math. Soc. 104 (1962), 308–333.
Feb 16, 2021 at 1:19 history asked Igor Belegradek CC BY-SA 4.0