Timeline for Can the eigenvalues of a real symmetric tensor be complex?
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
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| Feb 17, 2021 at 0:43 | vote | accept | Matt | ||
| Feb 17, 2021 at 0:25 | answer | added | Malkoun | timeline score: 6 | |
| Feb 16, 2021 at 21:27 | comment | added | Malkoun | I misread. I will delete my comments. | |
| Feb 16, 2021 at 17:16 | history | edited | LSpice | CC BY-SA 4.0 |
Name of reference
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| Feb 16, 2021 at 15:08 | comment | added | LSpice | @Malkoun, although it's not explicitly stated in the body, the title question indicates that the question is about real $T$, so the natural example you propose doesn't qualify. Indeed, if $T$ is real then $T(e_1, e_1)$ will also be real. | |
| Feb 16, 2021 at 13:08 | history | edited | gmvh |
Added top-level tags
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| Feb 16, 2021 at 12:09 | answer | added | Carlo Beenakker | timeline score: 4 | |
| Feb 16, 2021 at 5:13 | comment | added | lambda | Unless I'm misunderstanding something, $M$ is only real symmetric if you've already assumed $x$ is a real vector. A complex symmetric matrix can certainly have non-real eigenvalues. | |
| Feb 16, 2021 at 4:25 | comment | added | Matt | Thanks. Based on your example, if $T$ only has real components and is fully symmetric, then my argument with $M$ still holds and complex eigenvectors and eigenvalues are still impossible, no? | |
| Feb 16, 2021 at 0:22 | history | asked | Matt | CC BY-SA 4.0 |