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geocalc33
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About 6 months ago I asked for an analytic continuation of $\varphi(s)=\sum_{n\ge1} e^{-n^s}.$

From the answers and feedback I got, we know that an analytic continuation exists for $0<s<1$ and there is no analytic continuation for $s>1.$

What's the maximal analytic continuation of $\varphi(s)?$

Doing this will help me better understand how the function behaves.

As is stated in the comments, the main question is whether the line $\Re z=1$ is the natural boundary for the analytic continuation:

$$ \varphi(s)=\Gamma\left(1+\frac1s\right)+\sum_{n=0}^\infty\frac{(-1)^n}{n!}\zeta(-ns).$$

As noted by metamorphy, this series converges for complex $s\ne0$ with $\Re s<1$.

About 6 months ago I asked for an analytic continuation of $\varphi(s)=\sum_{n\ge1} e^{-n^s}.$

From the answers and feedback I got, we know that an analytic continuation exists for $0<s<1$ and there is no analytic continuation for $s>1.$

What's the maximal analytic continuation of $\varphi(s)?$

Doing this will help me better understand how the function behaves.

About 6 months ago I asked for an analytic continuation of $\varphi(s)=\sum_{n\ge1} e^{-n^s}.$

What's the maximal analytic continuation of $\varphi(s)?$

Doing this will help me better understand how the function behaves.

As is stated in the comments, the main question is whether the line $\Re z=1$ is the natural boundary for the analytic continuation:

$$ \varphi(s)=\Gamma\left(1+\frac1s\right)+\sum_{n=0}^\infty\frac{(-1)^n}{n!}\zeta(-ns).$$

As noted by metamorphy, this series converges for complex $s\ne0$ with $\Re s<1$.

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geocalc33
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Analytic Maximal analytic continuation of $\varphi(s)=\sum_{n\ge1} e^{-n^s}$ for $s<0$?

About 6 months ago I asked for an analytic continuation of $\varphi(s)=\sum_{n\ge1} e^{-n^s}.$

From the answers and feedback I got, we know that an analytic continuation exists for $0<s<1$ and there is no analytic continuation for $s>1.$

I'd like to understand whether or not there is anWhat's the maximal analytic continuation forof $s<0.$$\varphi(s)?$

Doing this will help me better understand how the function behaves.

Analytic continuation of $\varphi(s)=\sum_{n\ge1} e^{-n^s}$ for $s<0$?

About 6 months ago I asked for an analytic continuation of $\varphi(s)=\sum_{n\ge1} e^{-n^s}.$

From the answers and feedback I got, we know that an analytic continuation exists for $0<s<1$ and there is no analytic continuation for $s>1.$

I'd like to understand whether or not there is an analytic continuation for $s<0.$

Doing this will help me better understand how the function behaves.

Maximal analytic continuation of $\varphi(s)=\sum_{n\ge1} e^{-n^s}$

About 6 months ago I asked for an analytic continuation of $\varphi(s)=\sum_{n\ge1} e^{-n^s}.$

From the answers and feedback I got, we know that an analytic continuation exists for $0<s<1$ and there is no analytic continuation for $s>1.$

What's the maximal analytic continuation of $\varphi(s)?$

Doing this will help me better understand how the function behaves.

Source Link
geocalc33
  • 105
  • 2
  • 15

Analytic continuation of $\varphi(s)=\sum_{n\ge1} e^{-n^s}$ for $s<0$?

About 6 months ago I asked for an analytic continuation of $\varphi(s)=\sum_{n\ge1} e^{-n^s}.$

From the answers and feedback I got, we know that an analytic continuation exists for $0<s<1$ and there is no analytic continuation for $s>1.$

I'd like to understand whether or not there is an analytic continuation for $s<0.$

Doing this will help me better understand how the function behaves.