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Feb 10, 2021 at 22:11 comment added Daniel Litt Sort of fun to note that if you want to show that line bundles don't span $(K_0)_\mathbb{Q}$, you end up using that the square root of $2$ isn't rational.
Feb 10, 2021 at 22:08 comment added Daniel Litt @SWS: Thanks, looks good now!
Feb 10, 2021 at 18:25 history edited ssx CC BY-SA 4.0
deleted 18 characters in body
Feb 10, 2021 at 18:17 comment added ssx @DanielLitt Thanks for pointing this out; I think it is a mistake, which should be fixed now.
Feb 10, 2021 at 18:11 history edited ssx CC BY-SA 4.0
fixed error
Feb 10, 2021 at 16:07 comment added Daniel Litt I'm probably missing something silly -- why is the sentence "If the rank 2 bundle 𝒬 were in the subgroup of K0 generated by line bundles, then its K-theory class would therefore have to be 2[det(𝒬)]" true?
Feb 9, 2021 at 2:36 vote accept user45397
Feb 9, 2021 at 2:36 comment added user45397 Thanks, that helps.
Feb 9, 2021 at 2:25 history edited ssx CC BY-SA 4.0
added 993 characters in body
Feb 9, 2021 at 1:56 history edited ssx CC BY-SA 4.0
typo
Feb 9, 2021 at 1:27 history answered ssx CC BY-SA 4.0