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Feb 7, 2021 at 19:13 comment added rebo79 @MikaeldelaSalle I edited the post with the definition given by Triebel, and indeed is what you mean. At the very end in my particular case $\mathcal{H}_2$ is not closed in $\mathcal{H}_1$ (is a dense subspace instead), so I cannot expect that $P$ is still continuous when restricted to $\mathcal{H}_2$. I'm grateful with your remarks, thanks!
Feb 7, 2021 at 19:08 history edited rebo79 CC BY-SA 4.0
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Feb 7, 2021 at 13:38 comment added Mikael de la Salle Yes, that us what meant by compatible, and (I Guess) what Triebel means by $L(\{A0,A1\},\{A0,A1\})$. Note however that the projections need not be orthogonal.
Feb 6, 2021 at 23:06 comment added rebo79 Thinking about it, you mean that if $P: \mathcal{H}_1\to \mathcal{H}_1\cap X$ is the (linear continuous) projector, then $P$ when restricted to $\mathcal{H}_2$ is the (linear continuous) projector to $\mathcal{H}_2\cap X$, right?
Feb 6, 2021 at 22:47 comment added rebo79 @MikaeldelaSalle Sorry, but what do you mean by compatible projections? Although "compatible" is a widely used concept, I don't know it in this context and google doesn't seem to help me. Thanks!
Feb 6, 2021 at 22:20 comment added Mikael de la Salle I think that what your are missing is that you need that $H_1 \cap X$ and $H_2 \cap X$ are complemented subspaces of $H_1$ and $H_2$ with compatible projections.
Feb 6, 2021 at 21:08 history edited rebo79
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Feb 6, 2021 at 9:35 history asked rebo79 CC BY-SA 4.0