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Feb 11, 2021 at 10:05 vote accept Norbert
Feb 5, 2021 at 21:29 comment added Norbert Now it is clear. Thank you!
Feb 5, 2021 at 19:26 history edited KP Hart CC BY-SA 4.0
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Feb 5, 2021 at 19:23 comment added KP Hart No, I added further explanation above.
Feb 5, 2021 at 18:56 comment added Norbert Problem 3.12.24(c) in Engelking's General Topology states that the Cartesian product $X$ of compact Hausdorff spaces $\{X_s:s\in S\}$ is the Stone-Cech compactification of their $\Sigma$ product. By 2.7.14 from the same book the $\Sigma$ product of the family $\{X_s:s\in S\}$ is a set of the form $$\{x\in X: \operatorname{Card}(\{s\in S: x_s\neq a_s\})\leq \aleph_0 \}$$ for some $a\in X$. Clearly $\Sigma$ products are quite different from $X\setminus \{a\}$. So I don't think uncountable products of compact Hausdorff spaces are pretty compact. Am I right?
Feb 5, 2021 at 12:56 history answered KP Hart CC BY-SA 4.0