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Feb 4, 2021 at 10:37 comment added YCor @GeoffRobinson Oh, yes, I focussed on $A$ being conjugate to $A^{-1}$ after Alex B.'s answer. So, I should have said that the set of roots of $\Phi_n$ is stable under $x\mapsto x^m$ for $m$ coprime to $n$.
Feb 4, 2021 at 10:29 comment added Geoff Robinson @YCor : What you say is true, but I think you need a little more than stable under inversion: the roots of irreducible cyclotomic polynomials are all Galois conjugate to each other (Galois groups being over $\mathbb{Q}$).
Feb 4, 2021 at 10:24 comment added YCor Just as a motivation, if I'm correct, this is always true in $\mathrm{GL}_d(\mathbf{Q})$, due to the fact that the set of roots of every cyclotomic polynomial is stable under inversion. (And this is clearly false in $\mathrm{GL}_d(\mathbf{C})$ for every $d\ge 1$, just use a scalar matrix of finite order $\ge 3$.)
Feb 4, 2021 at 0:27 vote accept Caleb Eckhardt
Feb 4, 2021 at 0:00 history edited YCor CC BY-SA 4.0
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Feb 3, 2021 at 23:55 history edited YCor
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Feb 3, 2021 at 23:20 answer added Alex B. timeline score: 14
Feb 3, 2021 at 22:14 history asked Caleb Eckhardt CC BY-SA 4.0