Timeline for Does the Hodge decomposition hold for equivariant differential forms?
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| Feb 4, 2021 at 3:05 | comment | added | Ben Webster♦ | I don't have a good reference, but I know a good explanation of why this should work: the classifying space of any compact group can be written as a direct limit of Riemannian (actually, Kahler) manifolds: for example, $S^1$ gives $\mathbb{CP}^{\infty}$. So you can think of equivariant cohomology as an inverse limit of the cohomology of smooth Riemannian manifolds whose union is the Borel space. | |
| Feb 3, 2021 at 22:13 | history | asked | Hang | CC BY-SA 4.0 |