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Feb 3, 2021 at 17:39 comment added seub In other words, the formula is true for general oriented surfaces $S$ with or without boundary, as long as they're compact.
Feb 3, 2021 at 16:11 history edited Sebastian CC BY-SA 4.0
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Feb 3, 2021 at 15:44 comment added Sebastian The formula is not true for general surfaces $S$. But if you consider a compact oriented surface $S$ with non-trivial boundary, you can trivialise the principal $S^1$ bundle. This defines a connection 1-form on $S$, also called $\omega$ by abuse of notation, and Stokes theorem gives the holonomy formula. In the case of a closed orientable surface the formula holds as the degree of the $S^1$ bundle is an integer.
Feb 3, 2021 at 14:50 comment added seub I don't understand: first you provide a "proof" that the formula is true, and then you contradict yourself? The problem with the puncture seems inessential, obviously Stokes doesn't work stricto sensu for noncompact manifolds, so I assume same goes for the formula. Feel free to assume S is compact is my post.
Feb 3, 2021 at 13:59 history answered Sebastian CC BY-SA 4.0