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Feb 19, 2019 at 4:49 history edited François G. Dorais CC BY-SA 4.0
typo
Sep 11, 2010 at 20:24 comment added Joel David Hamkins András, yes, in that terminology, I am talking here just about complete lattices, which I had viewed as the natural context for the question. But perhaps one can find an induction-like characterization of CPOs? Give it a shot! Pete, thanks for accepting! But of course, it was also fine when you had accepted François' answer...
Sep 11, 2010 at 19:07 comment added Pete L. Clark Excellent! Thanks to both Joel and François -- as ever, I can only accept one answer. I think this is a real MO success story.
Sep 11, 2010 at 19:04 vote accept Pete L. Clark
Sep 11, 2010 at 18:30 comment added András Salamon The "lt" in part 2 seems to be missing the backslash.
Sep 11, 2010 at 18:29 comment added András Salamon Notational nit: in the terminology I am familiar with, a complete partial order (cpo) is a strictly more general notion than a complete lattice. en.wikipedia.org/wiki/Complete_partial_order
Sep 10, 2010 at 20:14 comment added Joel David Hamkins I also wonder this---I played around with many variations before hitting on this one. Your argument avoiding (1) in effect uses completeness, and I don't know any nice characterization avoiding (1) without assuming some completeness. Another question is: can we get a nice characterization that doesn't require the maximal element? I need this in order to know $sup(S)$ exists, and don't have any nice characterization without the maximal element.
Sep 10, 2010 at 18:25 comment added François G. Dorais Nice answer, Joel! I still wonder, since my condition 1 was not necessary, whether there is a variation of just 2 & 3 that has an if-and-only-if characterization.
Sep 10, 2010 at 17:50 history edited Joel David Hamkins CC BY-SA 2.5
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Sep 10, 2010 at 11:41 history edited Joel David Hamkins CC BY-SA 2.5
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Sep 10, 2010 at 11:20 history answered Joel David Hamkins CC BY-SA 2.5