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Feb 4, 2021 at 3:05 history made wiki Post Made Community Wiki by Ben Webster
Feb 2, 2021 at 17:30 comment added user44143 My process was to: 1) write down the formulas for $f, f’, f’’$, 2) define $\cos(x)^2$ in terms of $f$ and $f’$, 3) express $f’’$ in terms of $f$ and this expression for $\cos (x)^2$, 4) simplify
Feb 2, 2021 at 16:10 comment added Martin Rubey How did you find this beautiful equation? (I missed it, because my program looks for smaller powers first) No, I don't know of any solutions. It is very interesting that in this case, throwing away the zero coefficients makes the equation harder to find.
Feb 2, 2021 at 15:05 comment added user44143 For $\sin(\sin(\cdot))$ there is also the 2d-order equation $$(f'' - f '' f^2 + f f'^2)^2 - (1 - f^2 - f'^2) (1 - f^2)^2=0$$ which may or may not be nice. Do you know any of the other solutions for any of these equations?
Feb 2, 2021 at 9:22 history edited Martin Rubey CC BY-SA 4.0
correct weight
Feb 2, 2021 at 9:09 history edited Martin Rubey CC BY-SA 4.0
add weighted interpretation
Feb 2, 2021 at 4:24 history edited user44143 CC BY-SA 4.0
streamlined
Feb 1, 2021 at 21:21 history answered Martin Rubey CC BY-SA 4.0