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Timeline for The intersection form on a Jacobian

Current License: CC BY-SA 4.0

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Feb 2, 2021 at 10:00 comment added RandomMathUser I agree with your formula, but I am not sure how this helps to compute $q(u)$ in practice? Do you have a formula for $(u^\ast \Theta \cdot C)$?
Feb 1, 2021 at 14:56 comment added abx For $u\in\operatorname{End}^s(J) $, a standard computation shows that the class of $u^*\Theta $ in $\operatorname{NS}(J) $ corresponds to $u^2$. Therefore $q(u^2)=(u^*\Theta \cdot C)$, and by linearity $q(u)=\frac{1}{2} \bigl((1+u)^*\Theta \cdot C\bigr) -(u^*\Theta \cdot C)-g\,$, admittedly not a very nice formula.
Feb 1, 2021 at 10:35 history asked RandomMathUser CC BY-SA 4.0