Timeline for How to design a matrix function to meet the following conditions
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 31, 2021 at 17:26 | comment | added | A.Z. | If $q$ is the zero vector then $Xq$ and $q$ are not linear independent. Is $q=0$ allowed for your problem? | |
| Jan 29, 2021 at 16:53 | comment | added | Denny | I just come up with such possible function. Not sure if it is correct. $f(X,Q) = XQ-QX$. It is symmetric, rank 2 with $\{Xq, q\}$ if $Xq, \, q$ are L. I. And trace of $f(X,Q)$ is zero since tr$(XQ) = q^TXq$, so tr$(f)=q^TXq-q^TXq=0$. | |
| Jan 29, 2021 at 14:03 | review | First posts | |||
| Jan 29, 2021 at 15:26 | |||||
| Jan 29, 2021 at 13:57 | history | answered | A.Z. | CC BY-SA 4.0 |