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Mar 4 at 14:39 answer added Bence Racskó timeline score: 4
Feb 5, 2021 at 22:17 comment added Mikhail Skopenkov A rigorous discussion starts with an accurate statement rather than a proof ("derivation"). One should specify which exactly space of functions $\phi$ is considered and so on. E.g. in the reference recommended by Carlo Beenakker only C^2 smooth fucntions and C^2 smooth variations are considered. But minimizers even of smooth actions often cannot be found among smooth functions.
Feb 2, 2021 at 2:45 vote accept MathMath
Feb 2, 2021 at 2:40 comment added Pedro Lauridsen Ribeiro @Buzz the derivation can be made rigorous (see e.g. mathoverflow.net/a/349234/11211, mathoverflow.net/q/273254/11211 and physics.stackexchange.com/a/256496/16767). The problem is just the terminology employed in (some of) the physical literature - one is in fact looking for critical points of a family of action functionals over each compact region of space-time. Once properly defined, these are bona fide smooth functionals on the space of smooth field configurations, which on its turn can be endowed with a proper infinite-dimensional smooth manifold structure.
Feb 1, 2021 at 22:01 comment added Buzz I don't think there is a rigorous derivation. For one thing, it is possible to construct systems in which the physically-correct time evolution does not correspond to a minimization of the action. It could be a maximum of the action or—more crucially—a saddle point of the action. But what does it mean, precisely speaking, to be a saddle point of the action? Well, the fields obey the Euler-Lagrange equations....
Jan 29, 2021 at 21:33 comment added Willie Wong Most of my books are in my office; hopefully Igor Khavkine sees your question since I know for sure he has an answer to it. The correct formulation is also described in his paper arxiv.org/abs/1210.0802 but I don't know how much you would like the Jet language. I am also pretty sure that this is explained in Christodoulou's Action Principle and PDEs (Princeton Univ. Press). But I don't have my copy with me to give you a precise page reference.
Jan 29, 2021 at 13:00 comment added MathMath @WillieWong this is one reason. But also, all derivations I know come from physics books and thus there are some calculuations which seem unclear or poorly justified to me.
Jan 29, 2021 at 2:09 comment added Willie Wong What is unsatisfactory with the usual derivation that makes them non-rigorous? (Specifically, are you worried about the use of the compactly support perturbations? Are you worried about the fact that $S(\phi)$ is, for most field theories, necessarily infinite?)
Jan 28, 2021 at 20:10 answer added Carlo Beenakker timeline score: 2
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Jan 31, 2021 at 15:27
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Jan 28, 2021 at 17:39 history asked MathMath CC BY-SA 4.0