Timeline for How to design a matrix function to meet the following conditions
Current License: CC BY-SA 4.0
14 events
| when toggle format | what | by | license | comment | |
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| Jun 28, 2021 at 14:07 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Feb 28, 2021 at 14:01 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jan 31, 2021 at 15:30 | comment | added | Will Sawin | Do you want your function to be a matrix polynomial in $X$ and $Q$, with constant coefficients? | |
| Jan 29, 2021 at 13:57 | answer | added | A.Z. | timeline score: 1 | |
| Jan 27, 2021 at 16:54 | comment | added | Robert Israel | $Xq \ne q$ is not enough. You need $q$ and $Xq$ to be linearly independent. | |
| Jan 27, 2021 at 11:19 | comment | added | Denny | @A.Z. The matrix function here I mean, for example $f(X,Q) = 2X+3Q+4QX$. | |
| Jan 27, 2021 at 10:56 | comment | added | A.Z. | @Denny My function is a function of $X$ and $Q$. It just does not depend on the arguments. What do you mean by the term matrix function? Matrix functions have a strict definition, which does not immediately fit the form $f(X,Q)$. | |
| Jan 27, 2021 at 1:24 | history | edited | Denny | CC BY-SA 4.0 |
added 23 characters in body
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| Jan 27, 2021 at 1:24 | comment | added | Denny | @RobertIsrael I will try to put some constraints on it such as $Xq \neq q$. | |
| Jan 27, 2021 at 1:22 | comment | added | Denny | @A.Z. No. I want it to be in the function of $X$ and $Q$. But still helpful | |
| Jan 26, 2021 at 22:33 | comment | added | A.Z. | The constant function f(X, Q) = diag(1, -1, 0, ..., 0) satisfies all properties, but it is most likely not what you want, right? | |
| Jan 26, 2021 at 19:20 | review | Close votes | |||
| Feb 5, 2021 at 20:09 | |||||
| Jan 26, 2021 at 19:01 | comment | added | Robert Israel | (3) is not necessarily true for your example. The rank could be $0$ or $1$. | |
| Jan 26, 2021 at 17:39 | history | asked | Denny | CC BY-SA 4.0 |