Timeline for Prove zero slope point is global maximum for constrained function with binomials. Without restriction, objective function is non-concave
Current License: CC BY-SA 4.0
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| Mar 3, 2023 at 10:46 | comment | added | მამუკა ჯიბლაძე | I don't understand. When $M=J+1$, with your last formulation you get$$loss[q]=(v-CAP)q^M+(CAP-Mv+JC)q-J(C-v),$$for $v=CAP$ it is linear in $q$ with negative coefficient at $q$, so will attain lowest value at $q=1$. This function only has a global minimum strictly inside $(0,1)$ for $v>CAP$. | |
| Jan 26, 2021 at 13:51 | history | edited | Silvester | CC BY-SA 4.0 |
reformatted equations
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| Jan 26, 2021 at 13:45 | history | edited | Silvester | CC BY-SA 4.0 |
added 4 characters in body
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| Jan 26, 2021 at 11:41 | history | answered | Silvester | CC BY-SA 4.0 |