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Jan 24, 2021 at 16:01 comment added JHM Compare with mathoverflow.net/questions/235358/…
Jan 24, 2021 at 14:55 comment added JHM Moreover you might compare Ricci-Levi Civita's memoir eudml.org/doc/157997, especially pp.162, where the nonexistence of first order differential invariants on Riemannian manifolds is established. This nonexistence is old, long forgotten result, and which plays interesting role in proving the nonexistence of any tensorial expression for Einstein's gravitational energy density $T_{00}$. .
Jan 24, 2021 at 14:29 comment added JHM For the Hermitian manifold $(M, I, g)$, the $2$-form $g(\cdot, I \cdot)$ defines the symplectic $2$-form $\omega$ on $M$. Some argue that Darboux Theorem proves $\omega$ contains zero local geometric information. Moreover, if a riemannian manifold $(M,g)$ had a canonical $1$-form $\alpha$, then it would equivalently have a canonical vector field $X$ defined by $g(\cdot, X)=\alpha(\cdot)$. Except riemannian manifolds do not have canonical vector fields, e.g. euclidean space has no canonical vector field except the constant zero vector field.
Jan 23, 2021 at 22:59 history asked Dick Johnson CC BY-SA 4.0