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Bumped by Community user
Bumped by Community user
Minor grammar improvements and Math Jaxing
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Daniele Tampieri
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Let $\mu(x)dx$ be a mesuremeasure in $\mathbb{R}^{2n-2}$, where $\mu$ (  a $C^\infty$ and positive function) beis the density of the volume in the sense that $Vol_\mu(B_r)=\int_{B_r}\mu(x)dx$$\DeclareMathOperator{\Vol}{\mathrm{Vol}} \Vol_\mu(B_r)=\int_{B_r}\mu(x)dx$, where $B_r$ be the ball of raduceradius $r$ on $\mathbb{R}^{2n-2}$  . weNow suppose that $\mu(x)dx=d\Gamma$, By stockes: by Stokes's theorem we get$$Vol_\mu(B_r)=\int_{B_r}\mu(x)dx=\int_{B_r}d\Gamma=\int_{S_r}\Gamma$$ $$\Vol_\mu(B_r)=\int_{B_r}\mu(x)dx=\int_{B_r}d\Gamma=\int_{S_r}\Gamma$$ where  $S_t$ beis the sphere in $\mathbb{R}^{2n-3}$ the question is. The question is: can we explainexpress the area of $S_r$ as a function of the density $\mu$?

Let $\mu(x)dx$ be a mesure in $\mathbb{R}^{2n-2}$, where $\mu$ (  $C^\infty$ and positive function) be the density of the volume in the sense that $Vol_\mu(B_r)=\int_{B_r}\mu(x)dx$, where $B_r$ be the ball of raduce $r$ on $\mathbb{R}^{2n-2}$  . we suppose that $\mu(x)dx=d\Gamma$, By stockes we get$$Vol_\mu(B_r)=\int_{B_r}\mu(x)dx=\int_{B_r}d\Gamma=\int_{S_r}\Gamma$$ where$S_t$ be the sphere in $\mathbb{R}^{2n-3}$ the question is: can we explain the area of $S_r$ as a function of $\mu$?

Let $\mu(x)dx$ be a measure in $\mathbb{R}^{2n-2}$, where $\mu$ (a $C^\infty$ and positive function) is the density of the volume in the sense that $\DeclareMathOperator{\Vol}{\mathrm{Vol}} \Vol_\mu(B_r)=\int_{B_r}\mu(x)dx$, where $B_r$ be the ball of radius $r$ on $\mathbb{R}^{2n-2}$. Now suppose that $\mu(x)dx=d\Gamma$: by Stokes's theorem we get $$\Vol_\mu(B_r)=\int_{B_r}\mu(x)dx=\int_{B_r}d\Gamma=\int_{S_r}\Gamma$$ where  $S_t$ is the sphere in $\mathbb{R}^{2n-3}$. The question is: can we express the area of $S_r$ as a function of the density $\mu$?

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Relationship between volume density and area density

Let $\mu(x)dx$ be a mesure in $\mathbb{R}^{2n-2}$, where $\mu$ ( $C^\infty$ and positive function) be the density of the volume in the sense that $Vol_\mu(B_r)=\int_{B_r}\mu(x)dx$, where $B_r$ be the ball of raduce $r$ on $\mathbb{R}^{2n-2}$ . we suppose that $\mu(x)dx=d\Gamma$, By stockes we get$$Vol_\mu(B_r)=\int_{B_r}\mu(x)dx=\int_{B_r}d\Gamma=\int_{S_r}\Gamma$$ where$S_t$ be the sphere in $\mathbb{R}^{2n-3}$ the question is: can we explain the area of $S_r$ as a function of $\mu$?